Maths@CSHS

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Properties of regular polygons

Posted by maths083 on April 27, 2009

 

 

A regular polygon has all sides of equal length and all angles of equal magnitude. A polygon with n sides can be divided into n triangles. 

 

 

 

        The angle sum of the interior angles of an n-sided polygon is given by the 

formula:     S = [180(n − 2)] = (180n − 360) 

 

The magnitude of each of the interior angles of an n-sided polygon is given by: x = (180n − 360)⁄n

                                                              

                                                                   

The sum of the exterior angles of a regular polygon is 360

 

Example1: The diagram below shows a regular octagon. 

a Show that x = 45. 

b Find the size of angle y.

Solution

a x = 360°÷ 8 = 45°

b BOC is isosceles

              ∧              ∧ 

   then OBC and OCB are equal   

   x° + 2y°= 180°

   45° + 2y° = 180°

   2y°= 180° – 45°

   2y°= 135°

   y° = 67.5°

 

Example 2:Find the sum of the interior angles of an 8-sided convex polygon (octagon). 

Solution

Use the formula x°= (180n-360)°

x°= 180×8-360 = 1080 °

                                                         QUESTIONS

1 ABCD is a square. BD and AC are diagonals which meet at O.

a Find the size of each of the angles at O.

b What type of triangle is:

 

2 ABCDEF is a regular hexagon.

Find the value of:

a x                b y

 

3 The diagram shows a tessellation of regular hexagons and equilateral triangles.

State the values of a and b and use these to explain the existence of the tessellation.

 

                                                        ANSWERS

 

 1 a 90 

b i right-angled isosceles 

ii right-angled isosceles 

 

2 a 60 b 60  

 

a = 120, b = 60 The interior angles add up to 360 around a point so they tessellate. 

 

 

 

 

 

 

 

 

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